jimmythehand
Juniors
- Messages
- 2,071
so if 4 teams are on 28 points then I think the chances of any two of them being the same might be 6/200, or about 1 in 33. Quite possible really.
jimmythehand said:so if 4 teams are on 28 points then I think the chances of any two of them being the same might be 6/200, or about 1 in 33. Quite possible really.
waltzing Meninga said:Though if 4 teams were on 28 points the odds would be approx 4/200 (assuming that all point differentials are within 200 points of each other. i.e the odds are 1 in 50.
Bring back John Fifita said:Get 26 Players from both sides - each side starts on their own tryline, they bullrush each other, then have a brawl to the death, Last man standing wins the finals berth for his side.
I actually believe this system should replace golden point.
jimmythehand said:It's 6/200 isn't it?
P (AB) + P (AC) + P( AD) + P(BC) + P( BD) + P (CD)
Anyway it's bound to happen sooner or later.